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Alternating Series and Absolute Convergence

In this lesson you’ll learn how to handle series whose terms alternate between positive and negative, and the important distinction between absolute and conditional convergence.

An alternating series has terms that flip sign with each step

n=1(1)n+1an=a1a2+a3a4+\sum_{n=1}^{\infty} (-1)^{n+1} a_n = a_1 - a_2 + a_3 - a_4 + \cdots

where each term in the sequence (ignoring sign) satisfies

an>0a_n \gt 0

An alternating series converges if two conditions hold:

  1. The terms decrease in absolute value
an+1anfor all n large enougha_{n+1} \leq a_n \quad \text{for all } n \text{ large enough}
  1. The terms approach zero
limnan=0\lim_{n \to \infty} a_n = 0

When both conditions are met, the partial sums zigzag toward a finite limit, with each overshoot getting smaller.

A series converges absolutely if the series of absolute values also converges

an convergesan converges absolutely\sum |a_n| \text{ converges} \quad \Rightarrow \quad \sum a_n \text{ converges absolutely}

A series converges conditionally if it converges, but the series of absolute values diverges. The alternating harmonic series is the classic example: it converges, but the regular harmonic series (absolute values) diverges.

Why does this matter? Absolutely convergent series are well-behaved. You can rearrange the terms in any order and still get the same sum. Conditionally convergent series are fragile: rearranging terms can change the sum to any number you want, or even make it diverge. (This is the Riemann rearrangement theorem, and it’s wild.)

Example 1: Alternating harmonic series (conditional convergence)

n=1(1)n+1n=112+1314+\sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{n} = 1 - \frac{1}{2} + \frac{1}{3} - \frac{1}{4} + \cdots

Check the alternating series test. The terms 1/n are decreasing and approach 0, so the series converges.

Now check absolute convergence. The series of absolute values is the harmonic series, which diverges

n=11n=\sum_{n=1}^{\infty} \frac{1}{n} = \infty

So the alternating harmonic series converges conditionally. Its sum is ln 2, approximately 0.693.

The partial sums bounce above and below ln 2, with each bounce getting smaller. That zigzag pattern narrowing toward a limit is the signature of a convergent alternating series.

Example 2: Absolute convergence via the ratio test

n=1(1)nn2n\sum_{n=1}^{\infty} \frac{(-1)^n \cdot n}{2^n}

Check absolute convergence by looking at the series of absolute values

n=1n2n\sum_{n=1}^{\infty} \frac{n}{2^n}

Apply the ratio test

L=limn(n+1)/2n+1n/2n=limnn+12n=12L = \lim_{n \to \infty} \frac{(n+1)/2^{n+1}}{n/2^n} = \lim_{n \to \infty} \frac{n+1}{2n} = \frac{1}{2}

Since L = 1/2, which is less than 1, the series of absolute values converges. Therefore the original alternating series converges absolutely.

Absolute convergence is the stronger result. It means the series converges regardless of the signs.

Example 3: A series that fails the alternating series test

n=1(1)n+1nn+1\sum_{n=1}^{\infty} (-1)^{n+1} \frac{n}{n+1}

The terms n/(n + 1) approach 1 as n goes to infinity, not 0

limnnn+1=10\lim_{n \to \infty} \frac{n}{n+1} = 1 \neq 0

The alternating series test fails (condition 2 is not met). In fact, the nth-term test tells us this series diverges outright, since the terms don’t approach zero.

Compare this to the zigzag in Example 1. There, the bounces got smaller and smaller, narrowing toward ln 2. Here, the bounces stay roughly the same size forever, jumping between values near 0 and 1. No settling means no convergence.

Alternating series and convergence types matter in practice:

  • Fourier series for audio and image processing involve alternating terms
  • Error bounds for alternating series give guaranteed accuracy in numerical approximations
  • Taylor series for functions like ln(1 + x) and arctan(x) are alternating series
  • Game engines use truncated alternating series with known error bounds for fast approximations
The alternating series test requires that the terms $a_n$
The alternating harmonic series converges
A series converges absolutely if
If $\sum |a_n|$ diverges but $\sum a_n$ converges, the convergence is
The ratio test gives $L = 1/2$ for $\sum n/2^n$, so the series