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Convergence Tests

In this lesson you’ll learn the major convergence tests, which are your toolkit for deciding whether an infinite series adds up to a finite number or not.

The simplest check. If the terms don’t approach zero, the series can’t converge

If limnan0, then an diverges\text{If } \lim_{n \to \infty} a_n \neq 0, \text{ then } \sum a_n \text{ diverges}

Important: if the limit is 0, this test tells you nothing. The harmonic series has terms going to 0 but still diverges.

n=11npconverges if p>1,diverges if p1\sum_{n=1}^{\infty} \frac{1}{n^p} \quad \text{converges if } p \gt 1, \quad \text{diverges if } p \leq 1

The bigger the exponent p, the faster the terms shrink, and the easier it is for the sum to stay finite.

The red dots (p = 1, harmonic) keep climbing. The blue dots (p = 2) level off near π²/6. The green dots (p = 3) converge even faster to about 1.202.

n=0arn=a1rwhen r<1\sum_{n=0}^{\infty} ar^n = \frac{a}{1 - r} \quad \text{when } |r| \lt 1

If you have two series with positive terms where each term of one is less than or equal to the corresponding term of the other

  • If the bigger series converges, the smaller one does too
  • If the smaller series diverges, the bigger one does too

If two series have positive terms and

limnanbn=Lwhere 0<L<\lim_{n \to \infty} \frac{a_n}{b_n} = L \quad \text{where } 0 \lt L \lt \infty

then both series either converge or both diverge. This is often easier than direct comparison because you only need the limit of the ratio.

L=limnan+1anL = \lim_{n \to \infty} \left|\frac{a_{n+1}}{a_n}\right|
  • L less than 1: converges absolutely
  • L greater than 1: diverges
  • L equals 1: inconclusive

The ratio test is your go-to for series with factorials or exponentials.

L=limnannL = \lim_{n \to \infty} \sqrt[n]{|a_n|}

Same conclusions as the ratio test. Useful when the entire term is raised to the nth power.

Example 1: p-Series

Determine convergence of the following

n=11n2\sum_{n=1}^{\infty} \frac{1}{n^2}

This is a p-series with p = 2. Since 2 is greater than 1, the series converges. (Its sum is π²/6, but the p-series test only tells you it converges, not what it converges to.)

n=11n=n=11n1/2\sum_{n=1}^{\infty} \frac{1}{\sqrt{n}} = \sum_{n=1}^{\infty} \frac{1}{n^{1/2}}

This is a p-series with p = 1/2. Since 1/2 is less than or equal to 1, the series diverges.

Example 2: Ratio Test

Does the series converge or diverge?

n=1n!3n\sum_{n=1}^{\infty} \frac{n!}{3^n}

Apply the ratio test

L=limnan+1an=limn(n+1)!3n+13nn!L = \lim_{n \to \infty} \frac{a_{n+1}}{a_n} = \lim_{n \to \infty} \frac{(n+1)!}{3^{n+1}} \cdot \frac{3^n}{n!} =limn(n+1)!3n3n+1n!=limnn+13== \lim_{n \to \infty} \frac{(n+1)! \cdot 3^n}{3^{n+1} \cdot n!} = \lim_{n \to \infty} \frac{n+1}{3} = \infty

Since L = infinity, which is greater than 1, the series diverges. The factorial grows much faster than the exponential.

Example 3: Comparison Test

Does the following series converge?

n=11n2+1\sum_{n=1}^{\infty} \frac{1}{n^2 + 1}

For all n at least 1, we have n² + 1 greater than n², so

1n2+1<1n2\frac{1}{n^2 + 1} \lt \frac{1}{n^2}

We know the p-series with p = 2 converges. Since every term of our series is smaller than the corresponding term of a convergent series, our series converges by the comparison test.

Convergence tests matter whenever you use infinite series in practice:

  • Fourier series in audio processing need to converge for the signal reconstruction to work
  • Power series approximations in game engines are only valid within their radius of convergence
  • Numerical methods (like Newton’s method) are analyzed for convergence speed using ratio-like tests
  • Machine learning gradient descent convergence is studied with similar tools
If $\lim_{n \to \infty} a_n \neq 0$, the series $\sum a_n$
The p-series $\sum 1/n^p$ converges when
The ratio test gives $L = \infty$ for $\sum n!/3^n$, so the series
To show $\sum 1/(n^2 + 1)$ converges, you can compare it to
The ratio test is especially useful for series involving